Substituting you will get the second sum behaves the same as harmonic series and therefore can be approximated as logk. So just write tn and start expanding. Looking at these two, it is clear that n1 decreases in value slower than n2, or in other words, you will have more branches from the n1 portion of the tree. I believe you are right.
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Com › Questions › 13674719easy Solve T Nt N1+n By Iteration Method Stack Overflow.
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We Know That T1 C And T2 2c And Tn Tn1 + Tn2 + C.
You see the coefficients are fibonacci numbers themselves. i am trying to solve a recurrence using substitution method, Com › questions › 32669912solving a recurrence relation t nt n1+t n2+n.
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